M e d i a g o c c e = 190 + 193 + 201 3 = 195 {\displaystyle Media_{gocce}={190+193+201 \over 3}=195\!}
V g o c c i a = 1 c m 3 n g o c c e = 1 c m 3 195 = 0 , 0051282051 c m 3 = 5 , 12 m m 3 {\displaystyle V_{goccia}={1cm^{3} \over ngocce}={1cm^{3} \over 195}=0,0051282051cm^{3}=5,12mm^{3}\!}
A 1 a g o c c i a = 38 ∗ 40 = 1520 c m 2 {\displaystyle {A_{1^{a}goccia}}={38*40}=1520{cm^{2}}\!}
A 2 a g o c c i a = 35 c m ∗ 49 c m = 1715 c m 2 {\displaystyle {A_{{2^{a}}goccia}}={35cm*49cm}=1715{cm^{2}}\!}
A 3 a g o c c i a = ( 15 c m ) 2 ∗ π = 706 , 5 c m 2 {\displaystyle {A_{{3^{a}}goccia}}={{(15cm)^{2}}*\pi }=706,5{cm^{2}}\!}
M e d i a a r e e = 1520 c m 2 + 1715 c m 2 + 706 , 5 c m 2 3 = 1313 , 8 c m 2 {\displaystyle Media_{aree}={1520cm^{2}+1715cm^{2}+706,5cm^{2} \over 3}=1313,8cm^{2}\!}
h g o c c i a = V g o c c i a M e d i a a r e e = 38 , 9 n m {\displaystyle h_{goccia}={V_{goccia} \over Media_{aree}}=38,9nm\!} b g o c c i a = h g o c c i a 10 = 3 , 89 n m {\displaystyle b_{goccia}={h_{goccia} \over 10}=3,89nm\!}