Wikipedia:Reference desk/Archives/Mathematics/2019 December 21

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December 21

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Convergence of Cesàro means: how would a nonstandard proof look?

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It is a rather well-known result in basic analysis that if we have a real sequence   such that   for some real limit  , and we define  , then   as well. The standard proof (which I know) proceeds along these lines: given  , pick some   such that for all  ,  . Then split the sum for   to bits before and after term   using the triangle inequality, and write   for the maximum of the first   of the  . The sum of the terms after term   is bounded by  , and the sum of the terms before and including it is bounded by  , which is less than   if we pick   large enough. The result follows immediately.

My question is, how do you prove this result in nonstandard analysis with the infinitesimal-based definition of a limit? I am tempted to mimic the above: let   be an infinite hyperinteger and consider  . If   is finite then the respective term is a finite number over an infinite one, therefore infinitesimal. And if   is infinite then it is an infinitesimal over an infinity, so a second-order infinitesimal. The difficulty is that it seems to me that in the first half we are summing infinitely many infinitesimals, so we don't get the bound that we should have (as we need to prove that the entire sum is infinitesimal). How should I proceed? (I should mention that I am not really very experienced with nonstandard analysis, so I may be just misunderstanding something simple...) Double sharp (talk) 04:04, 21 December 2019 (UTC)[reply]

This seems like a good question that deserves a response. If you don't get an answer here then you might try mathoverflow; they seem to have a few people with expertise in nonstandard analysis. --RDBury (talk) 16:36, 24 December 2019 (UTC)[reply]